3x(4-x)=32

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Solution for 3x(4-x)=32 equation: 



3x(4-x)=32

We move all terms to the left:

3x(4-x)-(32)=0

We add all the numbers together, and all the variables

3x(-1x+4)-32=0

We multiply parentheses

-3x^2+12x-32=0

a = -3; b = 12; c = -32;
Δ = b2-4ac
Δ = 122-4·(-3)·(-32)
Δ = -240
Delta is less than zero, so there is no solution for the equation

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