3x(4x+15)=127

Solution for 3x(4x+15)=127 equation:

3x(4x+15)=127

We move all terms to the left:

3x(4x+15)-(127)=0

We multiply parentheses

12x^2+45x-127=0

a = 12; b = 45; c = -127;
Δ = b2-4ac
Δ = 452-4·12·(-127)
Δ = 8121
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(45)-\sqrt{8121}}{2*12}=\frac{-45-\sqrt{8121}}{24}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(45)+\sqrt{8121}}{2*12}=\frac{-45+\sqrt{8121}}{24}
$