3x(4x+5)=2(4x-5)

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Solution for 3x(4x+5)=2(4x-5) equation: 



3x(4x+5)=2(4x-5)

We move all terms to the left:

3x(4x+5)-(2(4x-5))=0

We multiply parentheses

12x^2+15x-(2(4x-5))=0



We calculate terms in parentheses: -(2(4x-5)), so:

2(4x-5)

We multiply parentheses

8x-10

Back to the equation:

-(8x-10)



We get rid of parentheses

12x^2+15x-8x+10=0

We add all the numbers together, and all the variables

12x^2+7x+10=0

a = 12; b = 7; c = +10;
Δ = b2-4ac
Δ = 72-4·12·10
Δ = -431
Delta is less than zero, so there is no solution for the equation

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