3x(4x-16)=0

Solution for 3x(4x-16)=0 equation:

3x(4x-16)=0

We multiply parentheses

12x^2-48x=0

a = 12; b = -48; c = 0;
Δ = b2-4ac
Δ = -482-4·12·0
Δ = 2304
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2304}=48$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-48)-48}{2*12}=\frac{0}{24}
=0
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-48)+48}{2*12}=\frac{96}{24}
=4
$