3x(4x-3)=12x2-9x

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Solution for 3x(4x-3)=12x2-9x equation: 



3x(4x-3)=12x^2-9x

We move all terms to the left:

3x(4x-3)-(12x^2-9x)=0

We multiply parentheses

12x^2-9x-(12x^2-9x)=0

We get rid of parentheses

12x^2-12x^2-9x+9x=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

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