3x(4x-7)+15=2x(6x+1)+38

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Solution for 3x(4x-7)+15=2x(6x+1)+38 equation: 



3x(4x-7)+15=2x(6x+1)+38

We move all terms to the left:

3x(4x-7)+15-(2x(6x+1)+38)=0

We multiply parentheses

12x^2-21x-(2x(6x+1)+38)+15=0



We calculate terms in parentheses: -(2x(6x+1)+38), so:

2x(6x+1)+38

We multiply parentheses

12x^2+2x+38

Back to the equation:

-(12x^2+2x+38)



We get rid of parentheses

12x^2-12x^2-21x-2x-38+15=0

We add all the numbers together, and all the variables

-23x-23=0

We move all terms containing x to the left, all other terms to the right

-23x=23

x=23/-23

x=-1

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