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3x(5+2x)-5(3x+7)=1/2
We move all terms to the left:
3x(5+2x)-5(3x+7)-(1/2)=0
We add all the numbers together, and all the variables
3x(2x+5)-5(3x+7)-(+1/2)=0
We multiply parentheses
6x^2+15x-15x-35-(+1/2)=0
We get rid of parentheses
6x^2+15x-15x-35-1/2=0
We multiply all the terms by the denominator
6x^2*2+15x*2-15x*2-1-35*2=0
We add all the numbers together, and all the variables
6x^2*2+15x*2-15x*2-71=0
Wy multiply elements
12x^2+30x-30x-71=0
We add all the numbers together, and all the variables
12x^2-71=0
a = 12; b = 0; c = -71;
Δ = b2-4ac
Δ = 02-4·12·(-71)
Δ = 3408
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{3408}=\sqrt{16*213}=\sqrt{16}*\sqrt{213}=4\sqrt{213}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-4\sqrt{213}}{2*12}=\frac{0-4\sqrt{213}}{24} =-\frac{4\sqrt{213}}{24} =-\frac{\sqrt{213}}{6} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+4\sqrt{213}}{2*12}=\frac{0+4\sqrt{213}}{24} =\frac{4\sqrt{213}}{24} =\frac{\sqrt{213}}{6} $
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