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3x(5x+2)=36
We move all terms to the left:
3x(5x+2)-(36)=0
We multiply parentheses
15x^2+6x-36=0
a = 15; b = 6; c = -36;
Δ = b2-4ac
Δ = 62-4·15·(-36)
Δ = 2196
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{2196}=\sqrt{36*61}=\sqrt{36}*\sqrt{61}=6\sqrt{61}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(6)-6\sqrt{61}}{2*15}=\frac{-6-6\sqrt{61}}{30} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(6)+6\sqrt{61}}{2*15}=\frac{-6+6\sqrt{61}}{30} $
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