3x(6=2x)-18+24

Solution for 3x(6=2x)-18+24 equation:

3x(6=2x)-18+24

We move all terms to the left:

3x(6-(2x)-18+24)=0

We add all the numbers together, and all the variables

3x(-2x+12)=0

We multiply parentheses

-6x^2+36x=0

a = -6; b = 36; c = 0;
Δ = b2-4ac
Δ = 362-4·(-6)·0
Δ = 1296
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1296}=36$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(36)-36}{2*-6}=\frac{-72}{-12}
=+6
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(36)+36}{2*-6}=\frac{0}{-12}
=0
$