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3x(7/3)=7

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Solution for 3x(7/3)=7 equation:



3x(7/3)=7
We move all terms to the left:
3x(7/3)-(7)=0
We add all the numbers together, and all the variables
3x(+7/3)-7=0
We multiply parentheses
21x^2-7=0
a = 21; b = 0; c = -7;
Δ = b2-4ac
Δ = 02-4·21·(-7)
Δ = 588
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
x_{1}=\frac{-b-\sqrt{\Delta}}{2a}
x_{2}=\frac{-b+\sqrt{\Delta}}{2a}

The end solution:
\sqrt{\Delta}=\sqrt{588}=\sqrt{196*3}=\sqrt{196}*\sqrt{3}=14\sqrt{3}
x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-14\sqrt{3}}{2*21}=\frac{0-14\sqrt{3}}{42} =-\frac{14\sqrt{3}}{42} =-\frac{\sqrt{3}}{3}
x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+14\sqrt{3}}{2*21}=\frac{0+14\sqrt{3}}{42} =\frac{14\sqrt{3}}{42} =\frac{\sqrt{3}}{3}

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