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3x(7x+19)=940x
We move all terms to the left:
3x(7x+19)-(940x)=0
We add all the numbers together, and all the variables
-940x+3x(7x+19)=0
We multiply parentheses
21x^2-940x+57x=0
We add all the numbers together, and all the variables
21x^2-883x=0
a = 21; b = -883; c = 0;
Δ = b2-4ac
Δ = -8832-4·21·0
Δ = 779689
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{779689}=883$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-883)-883}{2*21}=\frac{0}{42} =0 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-883)+883}{2*21}=\frac{1766}{42} =42+1/21 $
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