3x(7x-5)=0

Solution for 3x(7x-5)=0 equation:

3x(7x-5)=0

We multiply parentheses

21x^2-15x=0

a = 21; b = -15; c = 0;
Δ = b2-4ac
Δ = -152-4·21·0
Δ = 225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{225}=15$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-15)-15}{2*21}=\frac{0}{42}
=0
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-15)+15}{2*21}=\frac{30}{42}
=5/7
$