3x(x+(4/3))=-20

Solution for 3x(x+(4/3))=-20 equation:

3x(x+(4/3))=-20

We move all terms to the left:

3x(x+(4/3))-(-20)=0

We add all the numbers together, and all the variables

3x(x+(+4/3))-(-20)=0

We add all the numbers together, and all the variables

3x(x+(+4/3))+20=0

We multiply all the terms by the denominator


3x(x+(+4+20*3))=0

We add all the numbers together, and all the variables

3x(x+64)=0

We multiply parentheses

3x^2+192x=0

a = 3; b = 192; c = 0;
Δ = b2-4ac
Δ = 1922-4·3·0
Δ = 36864
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{36864}=192$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(192)-192}{2*3}=\frac{-384}{6}
=-64
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(192)+192}{2*3}=\frac{0}{6}
=0
$