3x(x+0,3)=6,08(3x-0,1)

Solution for 3x(x+0,3)=6,08(3x-0,1) equation:

3x(x+0.3)=6.08(3x-0.1)

We move all terms to the left:

3x(x+0.3)-(6.08(3x-0.1))=0

We multiply parentheses

3x^2+0.9x-(6.08(3x-0.1))=0


We calculate terms in parentheses: -(6.08(3x-0.1)), so:

6.08(3x-0.1)

We multiply parentheses

18.24x-0.608

Back to the equation:

-(18.24x-0.608)


We get rid of parentheses

3x^2+0.9x-18.24x+0.608=0

We add all the numbers together, and all the variables

3x^2-17.34x+0.608=0

a = 3; b = -17.34; c = +0.608;
Δ = b2-4ac
Δ = -17.342-4·3·0.608
Δ = 293.3796
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-17.34)-\sqrt{293.3796}}{2*3}=\frac{17.34-\sqrt{293.3796}}{6}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-17.34)+\sqrt{293.3796}}{2*3}=\frac{17.34+\sqrt{293.3796}}{6}
$