3x(x+10)=170

Solution for 3x(x+10)=170 equation:

3x(x+10)=170

We move all terms to the left:

3x(x+10)-(170)=0

We multiply parentheses

3x^2+30x-170=0

a = 3; b = 30; c = -170;
Δ = b2-4ac
Δ = 302-4·3·(-170)
Δ = 2940
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{2940}=\sqrt{196*15}=\sqrt{196}*\sqrt{15}=14\sqrt{15}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(30)-14\sqrt{15}}{2*3}=\frac{-30-14\sqrt{15}}{6}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(30)+14\sqrt{15}}{2*3}=\frac{-30+14\sqrt{15}}{6}
$