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3x(x+10)=52
We move all terms to the left:
3x(x+10)-(52)=0
We multiply parentheses
3x^2+30x-52=0
a = 3; b = 30; c = -52;
Δ = b2-4ac
Δ = 302-4·3·(-52)
Δ = 1524
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{1524}=\sqrt{4*381}=\sqrt{4}*\sqrt{381}=2\sqrt{381}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(30)-2\sqrt{381}}{2*3}=\frac{-30-2\sqrt{381}}{6} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(30)+2\sqrt{381}}{2*3}=\frac{-30+2\sqrt{381}}{6} $
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