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3x(x+11)=-16
We move all terms to the left:
3x(x+11)-(-16)=0
We add all the numbers together, and all the variables
3x(x+11)+16=0
We multiply parentheses
3x^2+33x+16=0
a = 3; b = 33; c = +16;
Δ = b2-4ac
Δ = 332-4·3·16
Δ = 897
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(33)-\sqrt{897}}{2*3}=\frac{-33-\sqrt{897}}{6} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(33)+\sqrt{897}}{2*3}=\frac{-33+\sqrt{897}}{6} $
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