3x(x+12)=2x(2x+4)=360

Solution for 3x(x+12)=2x(2x+4)=360 equation:

3x(x+12)=2x(2x+4)=360

We move all terms to the left:

3x(x+12)-(2x(2x+4))=0

We multiply parentheses

3x^2+36x-(2x(2x+4))=0


We calculate terms in parentheses: -(2x(2x+4)), so:

2x(2x+4)

We multiply parentheses

4x^2+8x

Back to the equation:

-(4x^2+8x)


We get rid of parentheses

3x^2-4x^2+36x-8x=0

We add all the numbers together, and all the variables

-1x^2+28x=0

a = -1; b = 28; c = 0;
Δ = b2-4ac
Δ = 282-4·(-1)·0
Δ = 784
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{784}=28$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(28)-28}{2*-1}=\frac{-56}{-2}
=+28
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(28)+28}{2*-1}=\frac{0}{-2}
=0
$