3x(x+2)+2=30+2x

Solution for 3x(x+2)+2=30+2x equation:

3x(x+2)+2=30+2x

We move all terms to the left:

3x(x+2)+2-(30+2x)=0

We add all the numbers together, and all the variables

3x(x+2)-(2x+30)+2=0

We multiply parentheses

3x^2+6x-(2x+30)+2=0

We get rid of parentheses

3x^2+6x-2x-30+2=0

We add all the numbers together, and all the variables

3x^2+4x-28=0

a = 3; b = 4; c = -28;
Δ = b2-4ac
Δ = 42-4·3·(-28)
Δ = 352
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{352}=\sqrt{16*22}=\sqrt{16}*\sqrt{22}=4\sqrt{22}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(4)-4\sqrt{22}}{2*3}=\frac{-4-4\sqrt{22}}{6}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(4)+4\sqrt{22}}{2*3}=\frac{-4+4\sqrt{22}}{6}
$