3x(x+2)=x+10

Solution for 3x(x+2)=x+10 equation:

3x(x+2)=x+10

We move all terms to the left:

3x(x+2)-(x+10)=0

We multiply parentheses

3x^2+6x-(x+10)=0

We get rid of parentheses

3x^2+6x-x-10=0

We add all the numbers together, and all the variables

3x^2+5x-10=0

a = 3; b = 5; c = -10;
Δ = b2-4ac
Δ = 52-4·3·(-10)
Δ = 145
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(5)-\sqrt{145}}{2*3}=\frac{-5-\sqrt{145}}{6}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(5)+\sqrt{145}}{2*3}=\frac{-5+\sqrt{145}}{6}
$