3x(x+2)=x+2

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Solution for 3x(x+2)=x+2 equation:



3x(x+2)=x+2
We move all terms to the left:
3x(x+2)-(x+2)=0
We multiply parentheses
3x^2+6x-(x+2)=0
We get rid of parentheses
3x^2+6x-x-2=0
We add all the numbers together, and all the variables
3x^2+5x-2=0
a = 3; b = 5; c = -2;
Δ = b2-4ac
Δ = 52-4·3·(-2)
Δ = 49
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{49}=7$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(5)-7}{2*3}=\frac{-12}{6} =-2 $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(5)+7}{2*3}=\frac{2}{6} =1/3 $

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