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3x(x+3)=22
We move all terms to the left:
3x(x+3)-(22)=0
We multiply parentheses
3x^2+9x-22=0
a = 3; b = 9; c = -22;
Δ = b2-4ac
Δ = 92-4·3·(-22)
Δ = 345
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(9)-\sqrt{345}}{2*3}=\frac{-9-\sqrt{345}}{6} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(9)+\sqrt{345}}{2*3}=\frac{-9+\sqrt{345}}{6} $
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