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3x(x+4)-(x2-5x+3)=0
We add all the numbers together, and all the variables
-(+x^2-5x+3)+3x(x+4)=0
We multiply parentheses
-(+x^2-5x+3)+3x^2+12x=0
We get rid of parentheses
-x^2+3x^2+5x+12x-3=0
We add all the numbers together, and all the variables
2x^2+17x-3=0
a = 2; b = 17; c = -3;
Δ = b2-4ac
Δ = 172-4·2·(-3)
Δ = 313
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(17)-\sqrt{313}}{2*2}=\frac{-17-\sqrt{313}}{4} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(17)+\sqrt{313}}{2*2}=\frac{-17+\sqrt{313}}{4} $
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