3x(x+4)=-5x-4

Solution for 3x(x+4)=-5x-4 equation:

3x(x+4)=-5x-4

We move all terms to the left:

3x(x+4)-(-5x-4)=0

We multiply parentheses

3x^2+12x-(-5x-4)=0

We get rid of parentheses

3x^2+12x+5x+4=0

We add all the numbers together, and all the variables

3x^2+17x+4=0

a = 3; b = 17; c = +4;
Δ = b2-4ac
Δ = 172-4·3·4
Δ = 241
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(17)-\sqrt{241}}{2*3}=\frac{-17-\sqrt{241}}{6}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(17)+\sqrt{241}}{2*3}=\frac{-17+\sqrt{241}}{6}
$