3x(x+4)=110

Solution for 3x(x+4)=110 equation:

3x(x+4)=110

We move all terms to the left:

3x(x+4)-(110)=0

We multiply parentheses

3x^2+12x-110=0

a = 3; b = 12; c = -110;
Δ = b2-4ac
Δ = 122-4·3·(-110)
Δ = 1464
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{1464}=\sqrt{4*366}=\sqrt{4}*\sqrt{366}=2\sqrt{366}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(12)-2\sqrt{366}}{2*3}=\frac{-12-2\sqrt{366}}{6}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(12)+2\sqrt{366}}{2*3}=\frac{-12+2\sqrt{366}}{6}
$