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3x(x+5)-2(x+5)=(x-2)(3x+5)
We move all terms to the left:
3x(x+5)-2(x+5)-((x-2)(3x+5))=0
We multiply parentheses
3x^2+15x-2x-((x-2)(3x+5))-10=0
We multiply parentheses ..
3x^2-((+3x^2+5x-6x-10))+15x-2x-10=0
We calculate terms in parentheses: -((+3x^2+5x-6x-10)), so:We add all the numbers together, and all the variables
(+3x^2+5x-6x-10)
We get rid of parentheses
3x^2+5x-6x-10
We add all the numbers together, and all the variables
3x^2-1x-10
Back to the equation:
-(3x^2-1x-10)
3x^2+13x-(3x^2-1x-10)-10=0
We get rid of parentheses
3x^2-3x^2+13x+1x+10-10=0
We add all the numbers together, and all the variables
14x=0
x=0/14
x=0
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