3x(x+5)=-7

Solution for 3x(x+5)=-7 equation:

3x(x+5)=-7

We move all terms to the left:

3x(x+5)-(-7)=0

We add all the numbers together, and all the variables

3x(x+5)+7=0

We multiply parentheses

3x^2+15x+7=0

a = 3; b = 15; c = +7;
Δ = b2-4ac
Δ = 152-4·3·7
Δ = 141
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(15)-\sqrt{141}}{2*3}=\frac{-15-\sqrt{141}}{6}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(15)+\sqrt{141}}{2*3}=\frac{-15+\sqrt{141}}{6}
$