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3x(x+7)=294
We move all terms to the left:
3x(x+7)-(294)=0
We multiply parentheses
3x^2+21x-294=0
a = 3; b = 21; c = -294;
Δ = b2-4ac
Δ = 212-4·3·(-294)
Δ = 3969
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{3969}=63$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(21)-63}{2*3}=\frac{-84}{6} =-14 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(21)+63}{2*3}=\frac{42}{6} =7 $
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