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3x(x+7)=35+2x
We move all terms to the left:
3x(x+7)-(35+2x)=0
We add all the numbers together, and all the variables
3x(x+7)-(2x+35)=0
We multiply parentheses
3x^2+21x-(2x+35)=0
We get rid of parentheses
3x^2+21x-2x-35=0
We add all the numbers together, and all the variables
3x^2+19x-35=0
a = 3; b = 19; c = -35;
Δ = b2-4ac
Δ = 192-4·3·(-35)
Δ = 781
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(19)-\sqrt{781}}{2*3}=\frac{-19-\sqrt{781}}{6} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(19)+\sqrt{781}}{2*3}=\frac{-19+\sqrt{781}}{6} $
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