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3x(x+8)+x=90
We move all terms to the left:
3x(x+8)+x-(90)=0
We add all the numbers together, and all the variables
x+3x(x+8)-90=0
We multiply parentheses
3x^2+x+24x-90=0
We add all the numbers together, and all the variables
3x^2+25x-90=0
a = 3; b = 25; c = -90;
Δ = b2-4ac
Δ = 252-4·3·(-90)
Δ = 1705
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(25)-\sqrt{1705}}{2*3}=\frac{-25-\sqrt{1705}}{6} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(25)+\sqrt{1705}}{2*3}=\frac{-25+\sqrt{1705}}{6} $
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