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3x(x+88)=0
We multiply parentheses
3x^2+264x=0
a = 3; b = 264; c = 0;
Δ = b2-4ac
Δ = 2642-4·3·0
Δ = 69696
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{69696}=264$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(264)-264}{2*3}=\frac{-528}{6} =-88 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(264)+264}{2*3}=\frac{0}{6} =0 $
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