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3x(x+9=9x^2+27x
We move all terms to the left:
3x(x+9-(9x^2+27x)=0
| g4− 3=1 | | 17t2+7t=0 | | 2(s+6)=14 | | 4x−102=2x−5 | | y+3.6=7.93 | | b+14=17 | | 2+6x2=3x+1 | | -m+9=2m | | x-9.2=2.82 | | 8j-2=9j+8 | | 6x+4-4x+1=23 | | 3(f-2)=2(f+0.5) | | 8j−2=9j+8 | | 24-y=48 | | 5x=440 | | 2(p-3)=6 | | 4^x-1=1/16 | | (3t)=2.7 | | 14+k=3k | | -4h=-7h+6 | | -2-8t=-9t | | 1/2x+2x+50=180 | | 17=-3+h | | 3r=84 | | -2−8t=-9t | | 16x-2.75=44.03 | | -3(x-1=9=15 | | 5b=4b+8 | | 5(3x+2)/4=-8 | | 2r+7=31 | | .5x−5=9x+3 | | 2x²-1=120 |