3x(x-1)-(x-3)(3x-2)=26

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Solution for 3x(x-1)-(x-3)(3x-2)=26 equation: 



3x(x-1)-(x-3)(3x-2)=26

We move all terms to the left:

3x(x-1)-(x-3)(3x-2)-(26)=0

We multiply parentheses

3x^2-3x-(x-3)(3x-2)-26=0

We multiply parentheses ..

3x^2-(+3x^2-2x-9x+6)-3x-26=0

We get rid of parentheses

3x^2-3x^2+2x+9x-3x-6-26=0

We add all the numbers together, and all the variables

8x-32=0

We move all terms containing x to the left, all other terms to the right

8x=32

x=32/8

x=4

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