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3x(x-10)=4
We move all terms to the left:
3x(x-10)-(4)=0
We multiply parentheses
3x^2-30x-4=0
a = 3; b = -30; c = -4;
Δ = b2-4ac
Δ = -302-4·3·(-4)
Δ = 948
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{948}=\sqrt{4*237}=\sqrt{4}*\sqrt{237}=2\sqrt{237}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-30)-2\sqrt{237}}{2*3}=\frac{30-2\sqrt{237}}{6} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-30)+2\sqrt{237}}{2*3}=\frac{30+2\sqrt{237}}{6} $
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