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3x(x-2)-x(x-6)=23(x-3)
We move all terms to the left:
3x(x-2)-x(x-6)-(23(x-3))=0
We multiply parentheses
3x^2-x^2-6x+6x-(23(x-3))=0
We calculate terms in parentheses: -(23(x-3)), so:We add all the numbers together, and all the variables
23(x-3)
We multiply parentheses
23x-69
Back to the equation:
-(23x-69)
2x^2-(23x-69)=0
We get rid of parentheses
2x^2-23x+69=0
a = 2; b = -23; c = +69;
Δ = b2-4ac
Δ = -232-4·2·69
Δ = -23
Delta is less than zero, so there is no solution for the equation
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