3x(x-2)=(1-2x)3-3(2-2x)

Solution for 3x(x-2)=(1-2x)3-3(2-2x) equation:

3x(x-2)=(1-2x)3-3(2-2x)

We move all terms to the left:

3x(x-2)-((1-2x)3-3(2-2x))=0

We add all the numbers together, and all the variables

3x(x-2)-((-2x+1)3-3(-2x+2))=0

We multiply parentheses

3x^2-6x-((-2x+1)3-3(-2x+2))=0


We calculate terms in parentheses: -((-2x+1)3-3(-2x+2)), so:

(-2x+1)3-3(-2x+2)

We multiply parentheses

-6x+6x+3-6

We add all the numbers together, and all the variables

-3

Back to the equation:

-(-3)


We add all the numbers together, and all the variables

3x^2-6x+3=0

a = 3; b = -6; c = +3;
Δ = b2-4ac
Δ = -62-4·3·3
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{6}{6}=1$