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3x(x-2)=3x-6
We move all terms to the left:
3x(x-2)-(3x-6)=0
We multiply parentheses
3x^2-6x-(3x-6)=0
We get rid of parentheses
3x^2-6x-3x+6=0
We add all the numbers together, and all the variables
3x^2-9x+6=0
a = 3; b = -9; c = +6;
Δ = b2-4ac
Δ = -92-4·3·6
Δ = 9
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{9}=3$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-9)-3}{2*3}=\frac{6}{6} =1 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-9)+3}{2*3}=\frac{12}{6} =2 $
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