If it's not what You are looking for type in the equation solver your own equation and let us solve it.
3x(x-3)=9
We move all terms to the left:
3x(x-3)-(9)=0
We multiply parentheses
3x^2-9x-9=0
a = 3; b = -9; c = -9;
Δ = b2-4ac
Δ = -92-4·3·(-9)
Δ = 189
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{189}=\sqrt{9*21}=\sqrt{9}*\sqrt{21}=3\sqrt{21}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-9)-3\sqrt{21}}{2*3}=\frac{9-3\sqrt{21}}{6} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-9)+3\sqrt{21}}{2*3}=\frac{9+3\sqrt{21}}{6} $
| d5+15=17 | | 1/2(b+8)=10 | | 6x+4x+14=180 | | 3(x-4)+2=3x+18 | | 3p-6=22 | | P=83p-6= | | 26=m-33 | | 8k=2k | | 3(q+1)=3 | | 5x+10+x-3=2x+24+35 | | u-20=18 | | -8x+4-2x=44 | | 2(x-3)2+1=73 | | 11=s+2.50 | | -4y-2=0 | | 2*x+1+2*x+3+2*x+5=57 | | j-85=12 | | (2n+6)=(n+3) | | 8-4y-4=16 | | 12.56=3.14×r^2 | | (y+3)(-4y-2)=0 | | 7^(3x+5)=7^(1-x) | | 14d-9d-3D+2d-d=9 | | (a+22)=12a=40 | | 3x+2+35=90 | | 22=4x+22 | | k7+4=11 | | -5-8x+25=-4 | | 85=2x+109 | | 15x+20=7x-5 | | 9x+24=60 | | (a*22)=12a=30 |