3x(x-4)=2x+3

Solution for 3x(x-4)=2x+3 equation:

3x(x-4)=2x+3

We move all terms to the left:

3x(x-4)-(2x+3)=0

We multiply parentheses

3x^2-12x-(2x+3)=0

We get rid of parentheses

3x^2-12x-2x-3=0

We add all the numbers together, and all the variables

3x^2-14x-3=0

a = 3; b = -14; c = -3;
Δ = b2-4ac
Δ = -142-4·3·(-3)
Δ = 232
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{232}=\sqrt{4*58}=\sqrt{4}*\sqrt{58}=2\sqrt{58}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-14)-2\sqrt{58}}{2*3}=\frac{14-2\sqrt{58}}{6}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-14)+2\sqrt{58}}{2*3}=\frac{14+2\sqrt{58}}{6}
$