3x(x-5)/2-2x(2x+4)/3=x2+61/6

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Solution for 3x(x-5)/2-2x(2x+4)/3=x2+61/6 equation: 



3x(x-5)/2-2x(2x+4)/3=x2+61/6

We move all terms to the left:

3x(x-5)/2-2x(2x+4)/3-(x2+61/6)=0

We add all the numbers together, and all the variables

-(+x^2+61/6)+3x(x-5)/2-2x(2x+4)/3=0

We get rid of parentheses

-x^2+3x(x-5)/2-2x(2x+4)/3-61/6=0

We calculate fractions

There is no solution for this equation

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