3x(x-5)=(3x+2)(x-1)

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Solution for 3x(x-5)=(3x+2)(x-1) equation: 



3x(x-5)=(3x+2)(x-1)

We move all terms to the left:

3x(x-5)-((3x+2)(x-1))=0

We multiply parentheses

3x^2-15x-((3x+2)(x-1))=0

We multiply parentheses ..

3x^2-((+3x^2-3x+2x-2))-15x=0



We calculate terms in parentheses: -((+3x^2-3x+2x-2)), so:

(+3x^2-3x+2x-2)

We get rid of parentheses

3x^2-3x+2x-2

We add all the numbers together, and all the variables

3x^2-1x-2

Back to the equation:

-(3x^2-1x-2)



We add all the numbers together, and all the variables

3x^2-15x-(3x^2-1x-2)=0

We get rid of parentheses

3x^2-3x^2-15x+1x+2=0

We add all the numbers together, and all the variables

-14x+2=0

We move all terms containing x to the left, all other terms to the right

-14x=-2

x=-2/-14

x=1/7

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