If it's not what You are looking for type in the equation solver your own equation and let us solve it.
3x(x-5)=5x-3
We move all terms to the left:
3x(x-5)-(5x-3)=0
We multiply parentheses
3x^2-15x-(5x-3)=0
We get rid of parentheses
3x^2-15x-5x+3=0
We add all the numbers together, and all the variables
3x^2-20x+3=0
a = 3; b = -20; c = +3;
Δ = b2-4ac
Δ = -202-4·3·3
Δ = 364
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{364}=\sqrt{4*91}=\sqrt{4}*\sqrt{91}=2\sqrt{91}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-20)-2\sqrt{91}}{2*3}=\frac{20-2\sqrt{91}}{6} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-20)+2\sqrt{91}}{2*3}=\frac{20+2\sqrt{91}}{6} $
| -5x+4=2x-31 | | 5x-7=1/2(11+15) | | A^2-18a=-80 | | 21-4x+6=38 | | -2=2/5t | | 1/3+x/5=7/3 | | 1/8g=-9 | | 2x+24+3x=180 | | x+3=29-x | | X+4=8+2x | | -5x4=2x-31 | | 5x+4=2x-31 | | 9x+27x-8=x | | 2x+4x-5=3x+1 | | 3z(2z+11)=11 | | 3b+2=6 | | y^2+1/2y+1/16=0 | | 0=141-16x^2 | | (5x+29)+(7x-11)=180 | | 0=x^2-3/4x-13 | | -7(x+3)=-2(x=3)-5x | | 17^{3x+7}=5 | | -677=6x-1 | | 229=-u+4 | | 5p-3p=4 | | 5/4=y−14. | | 3y-2(7)=8 | | 15/a=20/12 | | 2x-3+2x+3x+1=40 | | 10+1/3x=8 | | 4(d-4)+2=3(4+1) | | 11r=+60=16 |