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3x(x-6)+6=5x-6
We move all terms to the left:
3x(x-6)+6-(5x-6)=0
We multiply parentheses
3x^2-18x-(5x-6)+6=0
We get rid of parentheses
3x^2-18x-5x+6+6=0
We add all the numbers together, and all the variables
3x^2-23x+12=0
a = 3; b = -23; c = +12;
Δ = b2-4ac
Δ = -232-4·3·12
Δ = 385
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-23)-\sqrt{385}}{2*3}=\frac{23-\sqrt{385}}{6} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-23)+\sqrt{385}}{2*3}=\frac{23+\sqrt{385}}{6} $
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