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3x(x-8)=29
We move all terms to the left:
3x(x-8)-(29)=0
We multiply parentheses
3x^2-24x-29=0
a = 3; b = -24; c = -29;
Δ = b2-4ac
Δ = -242-4·3·(-29)
Δ = 924
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{924}=\sqrt{4*231}=\sqrt{4}*\sqrt{231}=2\sqrt{231}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-24)-2\sqrt{231}}{2*3}=\frac{24-2\sqrt{231}}{6} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-24)+2\sqrt{231}}{2*3}=\frac{24+2\sqrt{231}}{6} $
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