3x(x2)=4x(x+1)

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Solution for 3x(x2)=4x(x+1) equation: 



3x(x2)=4x(x+1)

We move all terms to the left:

3x(x2)-(4x(x+1))=0



We calculate terms in parentheses: -(4x(x+1)), so:

4x(x+1)

We multiply parentheses

4x^2+4x

Back to the equation:

-(4x^2+4x)



We get rid of parentheses

-4x^2+3xx2-4x=0

We add all the numbers together, and all the variables

-4x^2-4x+3xx2=0

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