3x(y+1)+4z(y+1)=

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Solution for 3x(y+1)+4z(y+1)= equation:


Simplifying
3x(y + 1) + 4z(y + 1) = 0

Reorder the terms:
3x(1 + y) + 4z(y + 1) = 0
(1 * 3x + y * 3x) + 4z(y + 1) = 0
(3x + 3xy) + 4z(y + 1) = 0

Reorder the terms:
3x + 3xy + 4z(1 + y) = 0
3x + 3xy + (1 * 4z + y * 4z) = 0

Reorder the terms:
3x + 3xy + (4yz + 4z) = 0
3x + 3xy + (4yz + 4z) = 0

Solving
3x + 3xy + 4yz + 4z = 0

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-4yz' to each side of the equation.
3x + 3xy + 4yz + -4yz + 4z = 0 + -4yz

Combine like terms: 4yz + -4yz = 0
3x + 3xy + 0 + 4z = 0 + -4yz
3x + 3xy + 4z = 0 + -4yz
Remove the zero:
3x + 3xy + 4z = -4yz

Add '-4z' to each side of the equation.
3x + 3xy + 4z + -4z = -4yz + -4z

Combine like terms: 4z + -4z = 0
3x + 3xy + 0 = -4yz + -4z
3x + 3xy = -4yz + -4z

Reorder the terms:
3x + 3xy + 4yz + 4z = -4yz + 4yz + -4z + 4z

Combine like terms: -4yz + 4yz = 0
3x + 3xy + 4yz + 4z = 0 + -4z + 4z
3x + 3xy + 4yz + 4z = -4z + 4z

Combine like terms: -4z + 4z = 0
3x + 3xy + 4yz + 4z = 0

The solution to this equation could not be determined.

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