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3x(2x-1)=2x+13
We move all terms to the left:
3x(2x-1)-(2x+13)=0
We multiply parentheses
6x^2-3x-(2x+13)=0
We get rid of parentheses
6x^2-3x-2x-13=0
We add all the numbers together, and all the variables
6x^2-5x-13=0
a = 6; b = -5; c = -13;
Δ = b2-4ac
Δ = -52-4·6·(-13)
Δ = 337
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-5)-\sqrt{337}}{2*6}=\frac{5-\sqrt{337}}{12} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-5)+\sqrt{337}}{2*6}=\frac{5+\sqrt{337}}{12} $
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