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3x(4x+5)=6x-3
We move all terms to the left:
3x(4x+5)-(6x-3)=0
We multiply parentheses
12x^2+15x-(6x-3)=0
We get rid of parentheses
12x^2+15x-6x+3=0
We add all the numbers together, and all the variables
12x^2+9x+3=0
a = 12; b = 9; c = +3;
Δ = b2-4ac
Δ = 92-4·12·3
Δ = -63
Delta is less than zero, so there is no solution for the equation
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