3x*2*5x=16

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Solution for 3x*2*5x=16 equation:



3x*2*5x=16
We move all terms to the left:
3x*2*5x-(16)=0
Wy multiply elements
30x^2*5-16=0
Wy multiply elements
150x^2-16=0
a = 150; b = 0; c = -16;
Δ = b2-4ac
Δ = 02-4·150·(-16)
Δ = 9600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:
$\sqrt{\Delta}=\sqrt{9600}=\sqrt{1600*6}=\sqrt{1600}*\sqrt{6}=40\sqrt{6}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-40\sqrt{6}}{2*150}=\frac{0-40\sqrt{6}}{300} =-\frac{40\sqrt{6}}{300} =-\frac{2\sqrt{6}}{15} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+40\sqrt{6}}{2*150}=\frac{0+40\sqrt{6}}{300} =\frac{40\sqrt{6}}{300} =\frac{2\sqrt{6}}{15} $

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