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3x*2x+3=288
We move all terms to the left:
3x*2x+3-(288)=0
We add all the numbers together, and all the variables
3x*2x-285=0
Wy multiply elements
6x^2-285=0
a = 6; b = 0; c = -285;
Δ = b2-4ac
Δ = 02-4·6·(-285)
Δ = 6840
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{6840}=\sqrt{36*190}=\sqrt{36}*\sqrt{190}=6\sqrt{190}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-6\sqrt{190}}{2*6}=\frac{0-6\sqrt{190}}{12} =-\frac{6\sqrt{190}}{12} =-\frac{\sqrt{190}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+6\sqrt{190}}{2*6}=\frac{0+6\sqrt{190}}{12} =\frac{6\sqrt{190}}{12} =\frac{\sqrt{190}}{2} $
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