3x*2x+3=288

Solution for 3x*2x+3=288 equation:

3x*2x+3=288

We move all terms to the left:

3x*2x+3-(288)=0

We add all the numbers together, and all the variables

3x*2x-285=0

Wy multiply elements

6x^2-285=0

a = 6; b = 0; c = -285;
Δ = b2-4ac
Δ = 02-4·6·(-285)
Δ = 6840
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{6840}=\sqrt{36*190}=\sqrt{36}*\sqrt{190}=6\sqrt{190}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-6\sqrt{190}}{2*6}=\frac{0-6\sqrt{190}}{12}
=-\frac{6\sqrt{190}}{12}
=-\frac{\sqrt{190}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+6\sqrt{190}}{2*6}=\frac{0+6\sqrt{190}}{12}
=\frac{6\sqrt{190}}{12}
=\frac{\sqrt{190}}{2}
$